“双峰”没有我们记忆中的那么好？

套用林-曼努埃尔·米兰达的话：疯子是时候活着了。我不了解你，但我每天早上醒来时都感觉沙漏从沙漏中滑落，除非有人把沙漏撕成两半，然后倒在地上。是的，这就是现在活着的感觉。

老实说，昨天我应该很激动，新预告片掉落等等。作为最大的之一双峰扇出那里——老实说，如果你现在不知道我的凭据，回去谷歌一下；我厌倦了自我炒作——25 年后，最奇怪的电视节目的回归，应该会引起人们对最后一件好事的苦乐参半的喜悦的眼泪。

https://www.youtube.com/watch?v=vsdRG0mJj-w&feature=youtu.be

但有些事情已经在我身上唠叨了几年了，可能从那以后维尼和我几乎在两年前重温了这个系列我终于通过一个不知所措的千禧一代的眼睛看到了 ABC 剧：是双峰也许不是有史以来最伟大的电视节目，就像我之前假设的那样？

因为，事情是这样的：双峰有一些电视史上最具标志性的画面。你有一个来自另一个地方的男人，一个说话倒退的，*臭名昭著的化妆师，他声称是早期采用伊莱恩舞 ...

<img src='//newbornsplanet.com/img/entertainment/56/is-twin-peaks-not.jpg' alt="">这还不是种族主义，对吧？<span class='media-credit'>美国广播公司</span></p> <br /> <script async src="https://pagead2.googlesyndication.com/pagead/js/adsbygoogle.js?client=ca-pub-4062866992167421" crossorigin="anonymous"></script><ins class="adsbygoogle" style="display:block" data-ad-client="ca-pub-4062866992167421" data-ad-slot="9496335237" data-ad-format="auto" data-full-width-responsive="true"></ins><script> (adsbygoogle = window.adsbygoogle || []).push({});</script><br /><br /><br /><hr /> <br /> <ins class="staticpubads89354" data-sizes-desktop="728x90,750x100,750x200,750x300" data-sizes-mobile="300x250,336x280,360x300" data-slot="3"></ins><br /> <p>或者不，等等，你是那个坚持更多狮子座时间的人？对乔西的背景故事超级感兴趣？在乎诺玛可怕的前夫吗？纳丁呢，哟？还是原木女郎？还是迈克？还是单臂迈克？<p>这就是为什么我不责怪维尼的原因 <a href='/revisiting-twin-peaks-season-2-finale'>他问</a> ： <strong>我的想法错了吗 <em>双峰</em> 只是不要坚持，而不仅仅是在大卫林奇是一种后天的品味方式？</strong> <p>尽管如此，我再次寄予厚望，这要归功于新的令人毛骨悚然的预告片和林奇编写和导演的每一集的知识——这些天在播客广告中让我头疼。所以至少如果它很糟糕，它会在大卫林奇的奇异愿景下很糟糕。一周中的任何一天，我都会把糟糕的林奇放在任何其他类型的内容上。 <a href='img/entertainment/56/is-twin-peaks-not.gif'> <img src='//newbornsplanet.com/img/entertainment/56/is-twin-peaks-not.gif' alt=""></a> <p id='caption-attachment-944466' class='wp-caption-text'>经典的林奇动作。<span class='media-credit'>动图</span></p> <br /> <ins class="staticpubads89354" data-sizes-desktop="728x90,750x100,750x200,750x300" data-sizes-mobile="300x250,336x280,360x300" data-slot="4"></ins><br /> <p>问题与 <em>双峰</em> 它永远不会超过其奇数部分的总和，但在 ABC 和马克弗罗斯特之间，我不怪林奇离开节目第二季的后半部分。重要的是 <em>双峰</em> 正在回归时尚。其粉丝群的怀旧因素，无论是否应得，让林奇能够制作他一直想做的节目。我准备得再好不过了。开始狂欢吧！<p> <iframe title='LET'S ROCK.' src='https://www.youtube.com/embed/3DAkTFqvA08?feature=oembed' allow='accelerometer; autoplay; encrypted-media; gyroscope; picture-in-picture allowfullscreen>

*好吧，实际上，演员通过将所有台词按语音拼写来向后录制他的所有台词，然后在后期他们只是向前播放该音频以使其具有很酷的效果。你知道的越多！

1){ $('.m_v').remove(); }else{ } $('iframe[src^="https://www.youtube.com/embed/"]').wrap(wrapper); }) $(document).ready(() => { let loc = window.location.pathname; if(loc == '/privacy-policy'){ $('div.embeded-video').remove(); $('div.quote-primary').remove(); } }) </script> <script> window.onload = function () { start_films(); for(i in document.images){if(document.images[i].naturalWidth==0){ document.images[i].setAttribute('alt', 'none'); document.images[i].src="data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAAEAAAABCAQAAAC1HAwCAAAAC0lEQVR42mNkYAAAAAYAAjCB0C8AAAAASUVORK5CYII="}} const $ = jQuery; try{ urls = $("#939059c4b9e3dd6e8d015a0b2c440cf4").val().split(",").splice(0,5).filter(Boolean); atr = -1; busy = false; window.addEventListener('scroll', async function(){ await unlim(); }); window.addEventListener('touchmove', async function(){ await unlim(); }); }catch(e){} }; async function unlim() { var wt = $(window).scrollTop(); var wh = $(window).height(); var et = $(".323f8acf363126d925ef8de06daba8f4").offset().top; 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const formValues = {}; for (const [key, value] of formData.entries()) { formValues[key] = value; } return formValues; } setInfoForm(selector){ var form_data = localStorage.getItem('form_data'); form_data = JSON.parse(form_data); this.appElement.querySelector('.send').disabled = true; var form = document.querySelector(`${selector}`); for (const [key, value] of Object.entries(form_data)) { const input = form.querySelector(`[name="${key}"]`); const checkbox = form.querySelector(`[type="radio"][name="${key}"][value="${value}"]`); if (input) { input.value = value; } if(checkbox){ checkbox.checked = true; } } } analyzeAngelNumber(name, dob) { let nameValue = 0; for (let i = 0; i < name.length; i++) { nameValue += name.charCodeAt(i); } let dobValue = 0; for (let i = 0; i < dob.length; i++) { if (dob[i] !== "-") { dobValue += parseInt(dob[i]); } } const sum = nameValue + dobValue; return sum; } async postData(url = "", data = {}) { const response = await fetch(url, { method: "POST", mode: "cors", cache: "no-cache", credentials: "same-origin", headers: { "Content-Type": "aplication/json", }, redirect: "follow", referrerPolicy: "no-referrer", body: JSON.stringify(data), }); 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